A force of 500 N is applied to a rod with a diameter of 4.00 mm.The stress in the rod is A) 5.38 $\times$ 10⁷ N/m². B) 4.66 $\times$ 10⁷ N/m². C) 4.25 $\times$ 10⁷ N/m². D) 3.98 $\times$ 10⁷ N/m². E) 2.75 $\times$ 10⁷ N/m².

Question

Quizplus · Accepted Answer

The stress in the rod can be calculated using the formula:

stress = force / area

The area of a rod with diameter 4.00 mm can be calculated using the formula for the area of a circle:

area = π(diameter/2)^2

area = π(4.00/2)^2 = 12.57×10^-6 m^2

Substituting the values into the stress formula:

stress = 500 N / 12.57×10^-6 m^2 = 3.98×10^7 N/m^2

Converting to scientific notation gives:

stress = 3.98×10^7 N/m^2 = 3.98 MPa

Therefore, the best choice is D: 3.98×10^7 N/m^2.

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