A 3.0 m organ pipe is open at both ends and contains air.The velocity of sound in air is 331 m/s.What is the wavelength of the lowest frequency mode?
A) 1.5 m
B) 3.0 m
C) 6.0 m
D) 9.0 m
E) 12.0 m

Question

Quizplus · Accepted Answer

The lowest frequency mode for an open-ended organ pipe is when the fundamental wavelength fits exactly twice the length of the pipe. Therefore, the wavelength (λ) is given by:
λ = 2L/n
where L is the length of the pipe and n is the mode number (in this case, the fundamental mode n=1). Substituting L=3.0 m and v=331 m/s we get:
λ = 2(3.0 m)/1 = 6.0 m
Therefore, the correct choice is C) 6.0 m.

A 30 M Organ Pipe Is Open at Both Ends and and Contains