A monatomic ideal gas at 27$^{\circ}$C undergoes an isobaric process from A to B followed by an isochoric process from B to C.What is the total work done in these two processes? (A = 2atm,1L; B = 2atm,2L; C = 1atm,2L)
A) 202 J
B) 231 J
C) 187 J
D) 195 J

Question

Quizplus · Accepted Answer

The work done in an isobaric process is given by W = PΔV. From A to B, the pressure P = 2 atm = 2 * 101325 Pa and the change in volume ΔV = 2L - 1L = 1L = 0.001 m³. Therefore, W = 2 * 101325 * 0.001 = 202.65 J. The isochoric process from B to C does no work since the volume does not change. Thus, the total work done is approximately 202 J.

A Monatomic Ideal Gas at 27 ∘^{\circ}∘ C Undergoes an Isobaric Process from a to B Followed

A Monatomic Ideal Gas at 27 $^{\circ}$ C Undergoes an Isobaric Process from a to B Followed