A thin metallic spherical shell of radius 50 cm has a total charge of 4.0 $ \mu$C placed on it.At the center of the shell is placed a point charge of 2.00 $ \mu$C.What is the electric field at a distance of 90 cm from the center of the spherical shell? A) 4.4 $\times$ 10⁴ N/C outward B) 2.7 $\times$ 10³ N/C inward C) 6.7 $\times$ 10⁴ N/C outward D) 8.8 $\times$ 10⁴ N/C outward E) 6.7 $\times$ 10⁴ N/C inward

Question

Quizplus · Accepted Answer

The electric field at a point outside a charged spherical shell is determined by the total charge enclosed. The total charge is the sum of the shell's charge (4.0 µC) and the point charge (2.0 µC), giving 6.0 µC. Using Coulomb's law, the electric field at 90 cm is calculated as E = k * Q / r² = (8.99 * 10^9 N m²/C²) * (6.0 * 10^-6 C) / (0.9 m)² = 6.7 * 10^4 N/C outward.

A Thin Metallic Spherical Shell of Radius 50 Cm Has μ \muμ

A Thin Metallic Spherical Shell of Radius 50 Cm Has $\mu$