A horizontal desk surface measures 1.3 m by 1.0 m.If the Earth's magnetic field has a magnitude of 0.44 mT and is directed 65$^{\circ}$below the horizontal,what is the magnetic flux through the desk surface? A) 1.1 $\times$ 10^-3 Wb B) 5.2 $\times$ 10^-4 Wb C) 3.2 $\times$ 10^-4 Wb D) 7.3 $\times$ 10^-3 Wb

Question

Quizplus · Accepted Answer

The magnetic flux through the desk surface can be calculated using the formula:
Φ = B*A*cosθ
where B is the magnitude of the magnetic field, A is the area of the surface, and θ is the angle between the magnetic field and the surface normal.

Substituting the given values, we get:
Φ = (0.44 mT) * (1.3 m * 1.0 m) * cos(65°) 
Φ = 0.44 * 1.3 * 1.0 * cos(65°) * 10^-4 Wb
Φ = 3.2 * 10^-4 Wb

Converting to scientific notation, the answer is:
Φ = 3.2 × 10^-4 Wb
which is equivalent to 3.2 × 10^-4 × 10^6 µWb
Thus, the answer is option C, 3.2 × 10^-4 Wb.

A Horizontal Desk Surface Measures 1 ∘^{\circ}∘ Below the Horizontal,what Is the Magnetic Flux Through the Desk

A Horizontal Desk Surface Measures 1 $^{\circ}$ Below the Horizontal,what Is the Magnetic Flux Through the Desk