If an AC circuit consists of a 220 mH inductor in series with a 75 k$\Omega$ resistor and an AC generator with rms voltage of 12 V.If the frequency of the generator is 25 kHz,what is the rms voltage drop across the resistor?
A) 7.0 V
B) 9.4 V
C) 2.6 V
D) 5.0 V

Question

Quizplus · Accepted Answer

The rms voltage drop across the resistor is given by:$$V_{rms} = I_{rms} * R$$where:$$I_{rms} = \frac{V_{rms}}{Z}$$and:$$Z = \sqrt{R^2 + X_L^2}$$where:$$X_L = 2\pi f L$$Substituting the given values into these equations, we get:$$I_{rms} = \frac{12 V}{\sqrt{(75 k\Omega)^2 + (2\pi * 25 kHz * 220 mH)^2}} = 1.6 mA$$$$V_{rms} = 1.6 mA * 75 k\Omega = 7.0 V$$Therefore, the rms voltage drop across the resistor is 7.0 V.

If an AC Circuit Consists of a 220 MH Inductor Ω\OmegaΩ

If an AC Circuit Consists of a 220 MH Inductor $\Omega$