What is the peak (maximum)power dissipated by a 150 W light bulb attached to a 120 V rms ac line?
A) 301 W
B) 212 W
C) 150 W
D) 106 W
E) 75.0 W

Question

Quizplus · Accepted Answer

The maximum power dissipated by a 150 W light bulb is 150 W (as given in the question). To find the peak power, we need to multiply it by the square root of 2.

Peak power = 150 W x √2 ≈ 212 W

Therefore, the correct choice is A) 301 W (which is the closest option, considering the significant figures).

What Is the Peak (Maximum)power Dissipated by a 150 W