At the Earth's surface,approximately 1000 W/m² is present due to solar radiation.At a latitude of 44.5 degrees North,the angle of the sun's rays,when the sun is highest in the sky on the winter solstice,are incident at an angle of 68 degrees from the vertical.What power is incident upon a 1.0 m $\times$ 1.5 m window in a vertical,south-facing wall at this time? A) 1390 W B) 930 W C) 560 W D) 370 W

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The correct answer is A.The power incident on the window is given by:P = I * A * cos(theta)where I is the solar radiation intensity, A is the area of the window, and theta is the angle of incidence.Plugging in the given values, we get:P = 1000 W/m^2 * 1.0 m * 1.5 m * cos(68 degrees) = 1390 W

At the Earth's Surface,approximately 1000 W/m2 Is Present Due to Solar

At the Earth's Surface,approximately 1000 W/m² Is Present Due to Solar