A light ray goes through two thick rectangular slabs of glass,each of the same uniform thickness.The first slab has index of refraction n₁ and the second n₂.If n₁ $\theta$_f B) $\theta$_i

Question

A light ray goes through two thick rectangular slabs of glass,each of the same uniform thickness.The first slab has index of refraction n₁ and the second n₂.If n₁ < n₂.How does the original angle of incidence $\theta$_i into the first slab compare to the final angle of refraction $\theta$_f where the ray leaves the second slab going back into air? A) $\theta$_i > $\theta$_f B) $\theta$_i < $\theta$_f C) $\theta$_i = $\theta$_f D) $\theta$_i = (n₁/n₂)$\theta$_f E) more information is needed

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The Answer of A light ray goes through two thick rectangular slabs of glass,each of the same uniform thickness.The first slab has index of refraction n₁ and the second n₂.If n₁ < n₂.How does the original angle of incidence $\theta$_i into the first slab compare to the final angle of refraction $\theta$_f where the ray leaves the second slab going back into air? A) $\theta$_i > $\theta$_f B) $\theta$_i < $\theta$_f C) $\theta$_i = $\theta$_f D) $\theta$_i = (n₁/n₂)$\theta$_f E) more information is needed

A Light Ray Goes Through Two Thick Rectangular Slabs of Glass,each