X-rays of wavelength 0.080 nm are used in a Bragg scattering experiment with a crystal.If the first order maximum is found at a grazing angle of 6.0$^{\circ}$,what is the plane spacing in the crystal?
A) 0.31 nm
B) 0.71 nm
C) 1.4 nm
D) 0.38 nm
E) 0.77 nm

Question

Quizplus · Accepted Answer

The Bragg's law states that 2d sinθ = nλ, where d is the distance between crystal planes, θ is the angle of incidence, n is the order of diffraction and λ is the wavelength of incident radiation.
Here, λ = 0.080 nm, θ = 6.0° and n = 1 (first order).
We need to find the value of d.
Using Bragg's law, we get: 
2d sinθ = nλ
2d sin6° = (1)(0.080 nm)
d = 0.038 nm
Therefore, the plane spacing in the crystal is 0.038 nm, which is approximately equal to 0.38 nm (option D).

X-Rays of Wavelength 0 ∘^{\circ}∘ ,What Is the Plane Spacing in the Crystal? A) 0

X-Rays of Wavelength 0 $^{\circ}$ ,What Is the Plane Spacing in the Crystal?
A) 0