In a radioactive decay, 2.37 $\times$ 10^-3 u are converted into kinetic energy.How much kinetic energy is this? (1 u = 1.66 $\times$ 10^-27 kg) A) 2.13 $\times$ 10¹⁴ J B) 9.31 $\times$ 10⁸ J C) 3.54 $\times$ 10^-13 J D) 3.93 $\times$ 10^-30 J E) 1.60 $\times$ 10^-13 J

Question

Quizplus · Accepted Answer

The formula for converting u into kinetic energy is E = mc^2, where m is the mass in kg and c is the speed of light (3 x 10^8 m/s). 
We are given the mass in u, so we need to convert it to kg first: 
2.37 u x 1.66 x 10^-27 kg/u = 3.94 x 10^-27 kg 
Now we can use the formula: 
E = (3.94 x 10^-27 kg) x (3 x 10^8 m/s)^2 = 3.54 x 10^-13 J 
Therefore, the correct choice is C.

In a Radioactive Decay, 2 ×\times× 10-3 U Are Converted into Kinetic Energy

In a Radioactive Decay, 2 $\times$ 10^-3 U Are Converted into Kinetic Energy