Given the contingency table shown here, find the probability that either event A₂ or event B₂ will occur. $$\begin{array} { |c | c | c | c | c | c | } \hline{ } & { A _ { 1 } } & A _ { 2 } & A _ { 3 } & A _ { 4 } & \text { Row Total } \ \hline B _ { 1 } & 12 & 26 & 42 & 68&148 \ \hline B _ { 2 } & 14 & 28 & 44 & 64 &150\ \hline B _ { 3 } & 18 & 32 & 47 & 72 &169\ \hline \text { Col Total } & 44 & 86 & 133 & 204 & 467 \ \hline \end{array}$$ A).4454 B).5054 C).0600

Question

Quizplus · Accepted Answer

The probability of event A₂ or event B₂ occurring is the sum of the probabilities of each event occurring. The probability of event A₂ occurring is 86/467 and the probability of event B₂ occurring is 150/467. Therefore, the probability of either event A₂ or event B₂ occurring is (86/467) + (150/467) = 236/467 = 0.5054.

Given the Contingency Table Shown Here, Find the Probability That