The probability that a certain daily flight's departure from ORD to LAX is delayed is .02. Over six months, this flight departs 180 times. What is the approximate Poisson probability that it will be delayed fewer than 2 times?
A).4471
B).3028
C).1257
D).1771

Question

Quizplus · Accepted Answer

We have the following information:

λ = expected number of delayed flights in 6 months = (0.02) * 180 = 3.6

We want to find P(X < 2), where X is the number of delayed flights in 6 months.

Using the Poisson probability formula:

P(X < 2) = e^(-λ) * (λ^0/0! + λ^1/1!)

P(X < 2) = e^(-3.6) * (1 + 3.6)

P(X < 2) = 0.1257

Therefore, the best choice is (C).

The Probability That a Certain Daily Flight's Departure from ORD