Hydrogen sulfide,H₂S,burns in the presence of oxygen, $\mathrm { O } _ { 2 }$ ,to produce water, $\mathrm { H } _ { 2 }$ O,and sulfur dioxide,SO₂.Through this reaction,is sulfur oxidized or reduced? 2 $\mathrm { H } _ { 2 }$ S + 3 $\mathrm { O } _ { 2 }$ ? 2 $\mathrm { H } _ { 2 }$ O + 2 $\mathrm { SO } _ { 2 }$ A)Sulfur is reduced. B)Sulfur is oxidized. C)Sulfur is both oxidized and reduced. D)Sulfur is neither oxidized nor reduced.

Question

Quizplus · Accepted Answer

Sulfur is oxidized because it goes from an oxidation state of -2 in hydrogen sulfide ($H_2S$) to +4 in sulfur dioxide ($SO_2$), indicating a loss of electrons.

Hydrogen Sulfide,H2S,burns in the Presence of Oxygen O2\mathrm { O } _ { 2 }O2​

Hydrogen Sulfide,H₂S,burns in the Presence of Oxygen $\mathrm { O } _ { 2 }$