How many grams of water, $\mathrm { H } _ { 2 }$ O,and propene, $\mathrm { C } _ { 3 }$ $\mathrm { H } _ { 6 }$ ,can be formed from the reaction of 6.0 g of 2-propanol, $\mathrm { C } _ { 3 }$ $\mathrm { H } _ { 8 }$ O? $\mathrm { C } _ { 3 }$ $\mathrm { H } _ { 8 }$ O ? $\mathrm { C } _ { 3 }$ $\mathrm { H } _ { 6 }$ + $\mathrm { H } _ { 2 }$ O 2-Propanol Propene Water
A)6.0 grams of propene,0.0 grams of water
B)1.8 grams of propene,4.2 grams of water
C)0.0 grams of propene,6.0 grams of water
D)4.2 grams of propene,1.8 grams of water

Question

Quizplus · Accepted Answer

The reaction conserves mass, so the total mass of products equals the mass of reactants. Given that 2-propanol ($\mathrm{C}_3\mathrm{H}_8\mathrm{O}$) decomposes into propene ($\mathrm{C}_3\mathrm{H}_6$) and water ($\mathrm{H}_2\mathrm{O}$), and starting with 6.0 g of 2-propanol, the mass of the products must also total 6.0 g. Since the question does not involve stoichiometry or molar mass calculations directly, the correct answer must account for the total mass being conserved and distributed between the two products, propene and water, as described in option D.

How Many Grams of Water H2\mathrm { H } _ { 2 }H2​

How Many Grams of Water $\mathrm { H } _ { 2 }$