How many grams of water can be produced by the combination of 8 grams of oxygen and 8 grams of hydrogen?
A)16 grams
B)10 grams
C)9 grams
D)8 grams

Question

Quizplus · Accepted Answer

The balanced chemical equation for the combination of hydrogen and oxygen to form water is:
2H2 + O2 → 2H2O

From the equation, we see that 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water. The molar mass of hydrogen is 2 g/mol and the molar mass of oxygen is 16 g/mol.

Given that we have 8 grams of oxygen and 8 grams of hydrogen, we can convert these masses to moles:
Moles of hydrogen = 8 g / 2 g/mol = 4 mol
Moles of oxygen = 8 g / 16 g/mol = 0.5 mol

Since oxygen is limiting in this reaction, we can use the number of moles of oxygen to calculate how much water is produced:
0.5 mol O2 × 2 mol H2O / 1 mol O2 × 18 g H2O / 1 mol H2O = 9 g H2O

Therefore, the answer is C) 9 grams of water can be produced.

How Many Grams of Water Can Be Produced by the Combination