Which of the following nuclear equations correctly describes beta emission?
A) $\begin{array} { c }
234\
90
\end{array}$ Th ? $\begin{array} { c }
234\
91
\end{array}$ Pa + $\begin{array} { c }
0 \
- 1
\end{array}$ e
B) $\begin{array} { c }
234\
90
\end{array}$ Th ? $\begin{array} { c }
234\
89
\end{array}$ Ac + $\begin{array} { c }
0 \
- 1
\end{array}$ e
C) $\begin{array} { c }
234\
90
\end{array}$ Th ? $\begin{array} { c }
235\
91
\end{array}$ Pa + $\begin{array} { c }
0 \
- 1
\end{array}$ e
D) $\begin{array} { c }
234\
90
\end{array}$ Th ? $\begin{array} { c }
0 \
- 1
\end{array}$ e
E)none of the above

Question

Which of the following nuclear equations correctly describes beta emission?
A) $\begin{array} { c } 
234\
90
\end{array}$ Th ? $\begin{array} { c } 
234\
91
\end{array}$ Pa + $\begin{array} { c } 
0 \
- 1
\end{array}$ e
B) $\begin{array} { c } 
234\
90
\end{array}$ Th ? $\begin{array} { c } 
234\
89
\end{array}$ Ac + $\begin{array} { c } 
0 \
- 1
\end{array}$ e
C) $\begin{array} { c } 
234\
90
\end{array}$ Th ? $\begin{array} { c } 
235\
91
\end{array}$ Pa + $\begin{array} { c } 
0 \
- 1
\end{array}$ e
D) $\begin{array} { c } 
234\
90
\end{array}$ Th ? $\begin{array} { c } 
0 \
- 1
\end{array}$ e
E)none of the above

Quizplus · Accepted Answer

In beta emission, a neutron in the nucleus is converted into a proton and an electron. The electron (beta particle) is emitted, and the atomic number increases by 1 while the mass number remains unchanged. Option A correctly shows thorium-234 (atomic number 90) decaying into protactinium-234 (atomic number 91) with the emission of an electron (beta particle), which is consistent with beta decay.

Which of the Following Nuclear Equations Correctly Describes Beta Emission 23490\begin{array} { c } 234\\90\end{array}23490​

Which of the Following Nuclear Equations Correctly Describes Beta Emission $\begin{array} { c } 234\\90\end{array}$