The current through two identical light bulbs connected in series is 0.25 A.The voltage across both bulbs is 110 V.The resistance of a single light bulb is
A)22 ohms.
B)44 ohms.
C)220 ohms.
D)440 ohms.
E)none of the above

Question

Quizplus · Accepted Answer

Using Ohm's Law, we can find the resistance of a single light bulb:

V = IR

Where V is the voltage across the bulb, I is the current through the bulb, and R is the resistance of the bulb.

We know the voltage across both bulbs is 110V, so the voltage across a single bulb is 55V. We also know the current through both bulbs is 0.25A, so the current through a single bulb is also 0.25A. Plugging these values into the equation, we get:

55V = 0.25A × R

Solving for R, we get:

R = 220 ohms

Therefore, the resistance of a single light bulb is 220 ohms (C).

The Current Through Two Identical Light Bulbs Connected in Series