In rabbits,spotted coat (S)is dominant to solid color (s)and black (B)is dominant to brown (b).A true-breeding black spotted rabbit is mated to a true-breeding brown solid rabbit to produce a heterozygous F₁ generation.Two F₁ individuals are mated,and you do not see a 9:3:3:1 (black spotted: black solid: brown spotted: brown solid)ratio of offspring,but instead see that almost all offspring are a non-recombinant phenotype.This tells you that A)that the genes for fur pattern (spotted vs.non-spotted)and fur color assort independently B)that the genes for fur pattern (spotted vs.non-spotted)and fur color are on the same chromosome C)that the genes for fur pattern (spotted vs.non-spotted)and fur color are on different chromosomes D)that the genes for fur pattern (spotted vs.non-spotted)and fur color are on the X-chromosome and Y-chromosome,repectively. E)that fur pattern (spotted vs.non-spotted)and fur color are maternally inherited

Question

Quizplus · Accepted Answer

The observation of almost all offspring displaying non-recombinant phenotypes (i.e., phenotypes that match the parental generation) suggests that the genes for fur pattern and fur color are closely linked on the same chromosome. This linkage reduces the likelihood of recombination between these genes during gamete formation, leading to the inheritance of these traits together more often than would be expected if they assorted independently.

In Rabbits,spotted Coat (S)is Dominant to Solid Color (S)and Black