A 330-g air track cart on a horizontal air track is attached to a string that goes over a pulley with a moment of inertia of 5.00 x 10^-6 kg∙m² and a radius of 1.35 cm. A 255-g mass hangs from the other end of the string and is released. What is the acceleration of the cart? A) 9.72 m/s² B) 7.14 m/s² C) 6.53 m/s² D) 4.74 m/s² E) 4.08 m/s²

Question

Quizplus · Accepted Answer

The acceleration can be found using the formula for a system involving a pulley: a = (m2 * g) / (m1 + m2 + I/r^2), where m1 is the mass of the cart, m2 is the hanging mass, I is the moment of inertia of the pulley, r is the radius of the pulley, and g is the acceleration due to gravity (9.81 m/s²). Plugging in the values, the acceleration is approximately 4.08 m/s².

A 330-G Air Track Cart on a Horizontal Air Track