A box slides down a 25.0° slope under its own weight. The coefficient of kinetic friction between the box and the slope is 0.350. What is the acceleration of the box? A) 1.03 m/s² B) 2.06 m/s² C) 1.22 m/s² D) 2.20 m/s² E) 2.44 m/s²

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The acceleration of the box is given by:$$a = g(sinθ - μkcosθ)$$where:* g is the acceleration due to gravity (9.8 m/s^2)* θ is the angle of the slope (25.0°)* μk is the coefficient of kinetic friction (0.350)Plugging in the values, we get:$$a = 9.8 m/s^2(sin25.0° - 0.350cos25.0°) = 1.03 m/s^2$$Therefore, the acceleration of the box is 1.03 m/s^2.

A Box Slides Down a 25