A ball is thrown at an angle 45° above the horizontal with an initial velocity of 20 m/s. What is the total time of flight of the ball before it hits the ground?
A) 9.8 s
B) 6.1 s
C) 2.9 s
D) 4.9 s
E) 1.5 s

Question

Quizplus · Accepted Answer

The time of flight for a projectile launched at an angle θ with initial velocity v is given by T = (2 * v * sin(θ)) / g. Here, v = 20 m/s, θ = 45°, and g = 9.8 m/s². Calculating gives T = (2 * 20 * sin(45°)) / 9.8 ≈ 2.9 s.

A Ball Is Thrown at an Angle 45° Above the Horizontal