If she uses an acceptance sampling plan of n = 10 and c = 2, what is the probability that, if this lot is 10% defective, it will be accepted for shipment without inspection?
A)0.9298
B)0.0702
C)0.8189
D)0.2198
E)0.5995

Question

Quizplus · Accepted Answer

The probability of accepting a lot without inspection is the probability that the number of defectives in the sample of 10 is less than or equal to the acceptance number of 2. Using binomial probabilities, we have:
P(X ≤ 2) = binomcdf(10,0.10,2) = 0.9298
Therefore, the probability that the lot will be accepted for shipment without inspection is 0.9298 or approximately 93%.

If She Uses an Acceptance Sampling Plan of N =