If he uses an acceptance sampling plan of n = 5 and c = 2, what is the probability that, if this batch is 40% defective, it will be rejected and receive 100% inspection prior to shipment?
A)0.1270
B)0.2730
C)0.3174
D)0.6826
E)0.7270

Question

Quizplus · Accepted Answer

We can use the binomial distribution to calculate the probability of getting 2 or more defects in a sample of 5 from a batch that is 40% defective:

P(reject batch) = P(2 or more defects in a sample of 5)
= 1 - P(0 defects) - P(1 defect)
= 1 - (0.6)^5 - 5*(0.4)*(0.6)^4 - (10/2)*(0.4)^2*(0.6)^3
= 0.3174

Therefore, the probability of the batch being rejected and receiving 100% inspection prior to shipment is 0.3174. So the best choice is C.

If He Uses an Acceptance Sampling Plan of N =