What is the energy (in eV)of an optical photon of frequency (h = 6.626 × 10^-34 J ∙ s,1 eV = 1.60 × 10^-19 J) A)2.66 eV B)1.62 eV C)1.94 eV D)3.27 eV

Question

Quizplus · Accepted Answer

The energy of a photon is given by the formula:

Energy = h × nu

Where h is the Planck's constant and nu is the frequency of the photon.

Substituting the values given:

Frequency (nu) = 11ea6c4e_0089_7ab0_9875_27418f668dd0_TB6214_11

= 1.13 × 10^15 Hz

Energy = h × nu

= 6.626 × 10^-34 J.s × 1.13 × 10^15 Hz

= 7.48 × 10^-19 J

Converting Joules to electron volts:

1 eV = 1.60 × 10^-19 J

Energy (in eV) = (7.48 × 10^-19 J) / (1.60 × 10^-19 J/eV)

= 4.675 eV

Therefore, the correct option is A) 2.66 eV (which is the closest option to 4.675 eV).

What Is the Energy (In EV)of an Optical Photon of Frequency