A certain astronomical telescope has a diameter of 5.60 m.What is the minimum angle of resolution for this telescope when it is forming images using light of wavelength 620 nm? A)1.11 × 10^-7 rad B)3.11 × 10^-7 rad C)2.70 × 10^-7 rad D)1.35 × 10^-7 rad E)4.05 × 10^-7 rad

Question

Quizplus · Accepted Answer

The minimum angle of resolution ($\theta$) for a telescope can be calculated using the formula $\theta = 1.22 \frac{\lambda}{D}$, where $\lambda$ is the wavelength of light and $D$ is the diameter of the telescope's aperture. Substituting $\lambda = 620 \times 10^{-9}$ m and $D = 5.60$ m into the formula gives $\theta = 1.22 \times \frac{620 \times 10^{-9}}{5.60}$ which calculates to approximately $1.35 \times 10^{-7}$ radians.

A Certain Astronomical Telescope Has a Diameter of 5