In a two-slit experiment,the slit separation is 3.00 ×
M.The interference pattern is created on a screen that is 2.00 m away from the slits.If the 7th bright fringe on the screen is 10.0 cm away from the central fringe,what is the wavelength of the light?
A)100 nm
B)204 nm
C)214 nm
D)224 nm
E)234 nm

Question

In a two-slit experiment,the slit separation is 3.00 × 
M.The interference pattern is created on a screen that is 2.00 m away from the slits.If the 7th bright fringe on the screen is 10.0 cm away from the central fringe,what is the wavelength of the light?
A)100 nm 
B)204 nm 
C)214 nm 
D)224 nm 
E)234 nm

Quizplus · Accepted Answer

We can use the equation for the position of the bright fringes:

y = (nλL) / d

where y is the distance from the central maximum to the nth bright fringe, λ is the wavelength, L is the distance from the slits to the screen, and d is the slit separation.

Plugging in the values given, we have:

10.0 cm = (7λ)(2.00 m) / (3.00 × 10⁻⁶ m)
Simplifying this equation, we get:

λ = 214 nm

Therefore, the answer is C.

In a Two-Slit Experiment,the Slit Separation Is 3