The inductor in a radio receiver carries a current of amplitude 0.200 A when an ac voltage of amplitude 2.40 V is across it at a frequency of 1400 Hz.What is the value of the inductance?
A)1.43 mH
B)1.36 mH
C)9.20 mH
D)4.42 mH
E)1.97 mH

Question

Quizplus · Accepted Answer

The inductive reactance $X_L$ is given by $X_L = \frac{V}{I}$, where $V$ is the voltage and $I$ is the current. Here, $X_L = \frac{2.40}{0.200} = 12 \, \Omega$. The inductive reactance is also given by $X_L = 2\pi f L$, where $f$ is the frequency and $L$ is the inductance. Solving for $L$, we have $L = \frac{X_L}{2\pi f} = \frac{12}{2\pi \times 1400} \approx 1.36 \, \text{mH}$.

The Inductor in a Radio Receiver Carries a Current of Amplitude