When 5.0 A at 110 V flows in the primary of an ideal transformer,how many amps at 24 V can flow in the secondary?
A)1.1 A
B)4.6 A
C)5.0 A
D)23 A

Question

Quizplus · Accepted Answer

In an ideal transformer, the power in the primary coil (P1) equals the power in the secondary coil (P2). Power is calculated as P = IV, where I is current and V is voltage. For the primary coil, P1 = 110V * 5.0A = 550W. To find the current in the secondary coil with a voltage of 24V, we use P2 = P1 = 550W, so I2 = P2 / V2 = 550W / 24V = 22.9167A, which rounds to 23A, making option D correct.

When 50 a at 110 V Flows in the Primary of of an Ideal