A 5.0-μF and a 12.0-μF capacitor are connected in series,and the series arrangement is connected in parallel to a 29.0-μF. Capacitor.How much capacitance would a single capacitor need to replace this combination of three capacitors?
A)33 μF
B)13 μF
C)16 μF
D)38 μF

Question

Quizplus · Accepted Answer

The equivalent capacitance of the two capacitors in series is:1/Ceq = 1/C1 + 1/C21/Ceq = 1/5.0 μF + 1/12.0 μFCeq = 3.75 μFThe equivalent capacitance of the three capacitors in parallel is:Ceq = C1 + C2 + C3Ceq = 3.75 μF + 29.0 μFCeq = 32.75 μFTherefore, a single capacitor with a capacitance of 32.75 μF would be needed to replace this combination of three capacitors.

A 50-μF and a 12