If 3.0 × 10¹⁵ electrons flow through a section of a wire of diameter 2.0 mm in 4.0 s,what is the current in the wire? (e = 1.60 × 10^-19C) A)0.12 mA B)0.24 mA C)7.5 × 10⁷ A D)7.5 × 10¹⁴ A

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Quizplus · Accepted Answer

The current I can be calculated using the formula I = Q/t, where Q is the charge and t is the time. Given that 3.0 × 10^15 electrons flow through the wire in 4.0 s, and each electron has a charge of 1.60 × 10^-19 C, the total charge Q = 3.0 × 10^15 electrons × 1.60 × 10^-19 C/electron = 4.8 × 10^-4 C. Therefore, the current I = Q/t = 4.8 × 10^-4 C / 4.0 s = 1.2 × 10^-4 C/s = 0.12 mA.

If 30 × 1015 Electrons Flow Through a Section of a a Wire

If 30 × 10¹⁵ Electrons Flow Through a Section of a a Wire