A 0.588-m string is tightly clamped at both ends.If the lowest standing wave frequency of the string is 326 Hz. How fast do waves travel on this string?
A)383 m/s
B)475 m/s
C)582 m/s
D)724 m/s

Question

Quizplus · Accepted Answer

The lowest standing wave frequency is given by:f1 = v/2Lwhere v is the wave speed and L is the string length.Solving for v, we get:v = 2f1L = 2(326 Hz)(0.588 m) = 383 m/s

A 0588-M String Is Tightly Clamped at Both Ends