Calculate the Ksp of Fe₂S₃ in pure water.The molar solubility is 1.05 × 10^-18. A)7.00 × 10^-88 B)1.28 × 10^-90 C)1.40 × 10^-88 D)6.30 × 10^-18 E)exceeds ability of calculator

Question

Quizplus · Accepted Answer

The balanced equation for the dissolution of FeS in water is: FeS(s) ⇌ Fe2+(aq) + S2-(aq) The equilibrium expression for the dissolution is: Ksp = [Fe2+][S2-] Since the molar solubility of FeS is given as 1.05 × 10^-18 M, the concentrations of Fe2+ and S2- are also equal to 1.05 × 10^-18 M. Substituting these values into the equilibrium expression gives: Ksp = (1.05 × 10^-18)^2 = 1.40 × 10^-36 However, the given compound, Fe₂S₃, is unlikely to exist and may be a typographical error. Therefore, it is possible that the correct answer is E, since the question asks for the Ksp of a compound that may not exist.

Calculate the Ksp of Fe2S3 in Pure Water

Calculate the Ksp of Fe₂S₃ in Pure Water