Determine the molar solubility of AgI in pure water.K_sp (AgI)= 8.51 × 10^-17. A) 9.22 × 10^-9 M B) 4.26 × 10^-17 M C) 8.51 × 10^-17 M D) 2.77 × 10^-6 M E) 4.40 × 10^-6 M

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Quizplus · Accepted Answer

The molar solubility of AgI in pure water can be calculated using the formula for the solubility product constant (Ksp). For AgI, which dissociates into Ag+ and I- ions, Ksp = [Ag+][I-]. Let the molar solubility be S, then Ksp = S^2. Solving for S gives S = sqrt(Ksp) = sqrt(8.51 × 10^-17) = 9.22 × 10^-9 M.

Determine the Molar Solubility of AgI in Pure Water