A solution is prepared by dissolving 16.2 g of benzene (C₆H₆)in 282 g of carbon tetrachloride (CCl₄).The concentration of benzene in this solution is ________ molal.The molar masses of C₆H₆ and CCl₄ are 78.1 g/mol and 154 g/mol,respectively. A)7.36 × 10^-4 B)0.736 C)0.102 D)0.0543 E)5.43

Question

Quizplus · Accepted Answer

Molality is calculated as moles of solute per kilogram of solvent. Moles of benzene = 16.2 g / 78.1 g/mol = 0.207 mol. Mass of CCl₄ in kg = 282 g / 1000 = 0.282 kg. Molality = 0.207 mol / 0.282 kg = 0.736 mol/kg.

A Solution Is Prepared by Dissolving 16