An aqueous solution is 0.387 M in HCl.What is the molality of the solution if the density is 1.23 g/mL?
A)0.115 m
B)0.387 m
C)0.315 m
D)0.411 m
E)0.318 m

Question

Quizplus · Accepted Answer

To find molality, use the formula: molality (m) = moles of solute / kg of solvent. First, calculate the mass of the solution: 1 L of solution = 1230 g (since density = 1.23 g/mL). Moles of HCl = 0.387 mol (since 0.387 M). Mass of HCl = 0.387 mol × 36.46 g/mol = 14.1 g. Mass of solvent (water) = 1230 g - 14.1 g = 1215.9 g = 1.2159 kg. Molality = 0.387 mol / 1.2159 kg = 0.318 m.

An Aqueous Solution Is 0