Determine the oxidation state of Sn in Sn(SO₄)₂. A)+2 B)+4 C)+6 D)0 E)-2

Question

Quizplus · Accepted Answer

In the given compound, the sum of oxidation states of all atoms must be equal to zero as the compound is neutral.

Let's assume the oxidation state of sulfur (S) to be -2 (most common) and oxygen (O) to be -2.

Then, we can write the compound as Sn(SO4)2, where the oxidation state of Sn can be calculated as follows:

(+x) + (2×-2) + 2(-2) = 0
x - 4 - 4 = 0
x = +8

Therefore, the oxidation state of Sn in the given compound is +4, which corresponds to option B.

Determine the Oxidation State of Sn in Sn(SO4)2