You have 2.00 L of a buffer solution which is composed of 0.250 M HClO and 0.650 M KClO.Calculate the pH of the solution after the addition of 265 mL of 1.00 M HCl.The K_a for HClO is 3.0 × 10^-8. A) 7.65 B) 11.65 C) 7.89 D) 11.14 E) 4.66

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The correct answer is A because the pH of the solution after the addition of 265 mL of 1.00 M HCl is 7.65. This is because the addition of HCl will decrease the pH of the solution, and the buffer will resist this change by donating H+ ions to the solution. The equilibrium constant for the dissociation of HClO is 3.0 × 10-8, so the concentration of H+ ions in the solution will be 3.0 × 10-8 M. The pH of the solution can be calculated using the equation pH = -log[H+], so the pH of the solution is 7.65.

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