A solution containing CaCl₂ is mixed with a solution of Li₂C₂O₄ to form a solution that is 3.5 × 10^-4 M in calcium ion and 2.33 × 10^-4M in oxalate ion.What will happen once these solutions are mixed? K_sp (CaC₂O₄)= 2.3 × 10^-9. A) Nothing will happen since both calcium chloride and lithium oxalate are soluble compounds. B) Nothing will happen K_sp Q for all possible precipitants. C) A precipitate will form as calcium oxalate is not soluble to any extent. D) A precipitate will form since Q K_sp for calcium oxalate. E) There is not enough information to determine.

Question

A solution containing CaCl₂ is mixed with a solution of Li₂C₂O₄ to form a solution that is 3.5 × 10^-4 M in calcium ion and 2.33 × 10^-4M in oxalate ion.What will happen once these solutions are mixed? K_sp (CaC₂O₄)= 2.3 × 10^-9. A) Nothing will happen since both calcium chloride and lithium oxalate are soluble compounds. B) Nothing will happen K_sp > Q for all possible precipitants. C) A precipitate will form as calcium oxalate is not soluble to any extent. D) A precipitate will form since Q > K_sp for calcium oxalate. E) There is not enough information to determine.

Quizplus · Accepted Answer

The given solutions contain calcium ions and oxalate ions. The product of their concentrations will give the ion product Q. The solubility product constant (Ksp) of calcium oxalate is also given. If Q is greater than Ksp, a precipitate will form.

The ion product for calcium oxalate is [Ca2+][C2O4 2-] = (3.5 × 10^-4 M)(2.33 × 10^-4 M) = 8.155 × 10^-9. This value is greater than the given Ksp value of 2.3 × 10^-9. Therefore, Q is greater than Ksp and calcium oxalate will precipitate out of solution.

Therefore, the correct answer is D, and a precipitate will form since Q > Ksp for calcium oxalate.

A Solution Containing CaCl2 Is Mixed with a Solution of Li2C2O4

A Solution Containing CaCl₂ Is Mixed with a Solution of Li₂C₂O₄