Calculate the pH of a solution formed by mixing 250.0 mL of 0.900 M NH₄Cl with 250.0 mL of 1.60 M NH₃.The K_b for NH₃ is 1.8 × 10^-5. A) 8.25 B) 9.18 C) 9.50 D) 10.12 E) 10.83

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Quizplus · Accepted Answer

The correct answer is C because the pH of the solution is 9.50. This can be calculated using the Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]), where pKa is the dissociation constant of the weak acid (NH4+), [A-] is the concentration of the weak base (NH3), and [HA] is the concentration of the weak acid (NH4Cl). In this case, pKa = 9.25, [A-] = 0.800 M, and [HA] = 0.450 M. Plugging these values into the equation gives pH = 9.50.

Calculate the PH of a Solution Formed by Mixing 250