The osmotic pressure of a solution formed by dissolving 25.0 mg of aspirin (C₉H₈O₄)in enough water to make 0.250 L of solution at 25°C is ________ atm. A) 13.6 B) 1.14 × 10^-3 C) 0.0136 D) 2.45 E) 1.38

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Quizplus · Accepted Answer

The osmotic pressure (π) can be calculated using the formula π = (n/V)RT. First, calculate the moles of aspirin: 25.0 mg = 0.025 g, molar mass of aspirin = 180.16 g/mol, so moles = 0.025 g / 180.16 g/mol = 1.39 × 10^-4 mol. Volume = 0.250 L. Using R = 0.0821 L·atm/mol·K and T = 298 K, π = (1.39 × 10^-4 mol / 0.250 L) × 0.0821 × 298 = 0.0136 atm.

The Osmotic Pressure of a Solution Formed by Dissolving 25