Determine DH_solute for KBr if the DH_solution(KBr)= +19.9 kJ/mol and the ΔH_hydration(KBr)= -670.kJ/mol. A) +650 kJ/mol B) -650 kJ/mol C) +690 kJ/mol D) -710 kJ/mol E) -690 kJ/mol

Question

Quizplus · Accepted Answer

The enthalpy of solution is the sum of the enthalpy of solute and the enthalpy of hydration: ΔH_solution = ΔH_solute + ΔH_hydration. Rearranging gives ΔH_solute = ΔH_solution - ΔH_hydration = 19.9 kJ/mol - (-670 kJ/mol) = 19.9 kJ/mol + 670 kJ/mol = 689.9 kJ/mol, which rounds to +690 kJ/mol.

Determine DHsolute for KBr If the DHsolution (KBr)= +19

Determine DH_solute for KBr If the DH_solution(KBr)= +19