What is the temperature of 100.8 g of N₂ that exerts a pressure of 23.8 atm in a 6.51 L container? A) 524K B) 489K C) 778K D) 261K E) 340K

Name: What is the temperature of 100.8 g of N 2 that exerts a pressure of 23.8 atm in a 6.51 L container? A) 524K B) 489K C) 778K D) 261K E) 340K
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Quizplus · Accepted Answer

Using the ideal gas law PV = nRT, where n = mass/molar mass = 100.8 g / 28.02 g/mol = 3.6 mol, R = 0.0821 L·atm/mol·K, solve for T: T = (23.8 atm * 6.51 L) / (3.6 mol * 0.0821 L·atm/mol·K) = 524 K.

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