Determine the oxidation state of Ti in Ti(SO₄)₂. A) +2 B) +4 C) +6 D) 0 E) -2

Question

Quizplus · Accepted Answer

The oxidation states of oxygen and sulfur in the complex are -2 and +6, respectively. The sum of the oxidation states of all the ligands must equal the charge of the complex, which is 0 in this case. Let x be the oxidation state of Ti. Then, we can set up the following equation:

x + (-2) + 6 + (-2) + 0 + 0 + (-2) + 0 + 0 + 0 + (-2) + 0 = 0

Simplifying this equation gives:

x + 0 = 0

Therefore, the oxidation state of Ti is 0.

Determine the Oxidation State of Ti in Ti(SO4)2

Determine the Oxidation State of Ti in Ti(SO₄)₂