Balance the chemical equation given below,and determine the number of milliliters of 0.00300 M phosphoric acid required to neutralize 40.00 mL of 0.00150 M calcium hydroxide. ________ Ca(OH)₂(aq)+ ________ H₃PO₄(aq)→ ________ Ca₃(PO₄)₂(aq)+ ________ H₂O(l) A) 2.70 mL B) 13.3 mL C) 20.0 mL D) 30.0 mL

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Quizplus · Accepted Answer

The balanced equation is 3Ca(OH)2 + 2H3PO4 → Ca3(PO4)2 + 6H2O. Using stoichiometry, 40.00 mL of 0.00150 M Ca(OH)2 requires 13.3 mL of 0.00300 M H3PO4 for neutralization.

Balance the Chemical Equation Given Below,and Determine the Number of Milliliters