How many milliliters of 0.260 M Na₂S are needed to react with 25.00 mL of 0.315 M AgNO₃?
Na₂S(aq) + 2 AgNO₃(aq) → 2 NaNO₃(aq) + Ag₂S(s)

Question

How many milliliters of 0.260 M Na₂S are needed to react with 25.00 mL of 0.315 M AgNO₃? Na₂S(aq)+ 2 AgNO₃(aq)→ 2 NaNO₃(aq)+ Ag₂S(s) A)15.1 mL B)30.3 mL C)41.3 mL D)60.6 mL

Quizplus · Accepted Answer

The balanced equation shows that 1 mole of Na2S reacts with 2 moles of AgNO3. Calculate moles of AgNO3: 0.315 M * 0.025 L = 0.007875 moles. Moles of Na2S needed: 0.007875 / 2 = 0.0039375 moles. Volume of Na2S: 0.0039375 moles / 0.260 M = 0.0151 L = 15.1 mL.

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