What is the concentration of NO₃^- ions in a solution prepared by dissolving 15.0 g of Ca(NO₃)₂ in enough water to produce 300.mL of solution? A)0)152 M B)0)305 M C)0)403 M D)0)609 M

Question

Quizplus · Accepted Answer

First, calculate the molar mass of Ca(NO3)2, which is approximately 164.1 g/mol. Then, find the moles of Ca(NO3)2 by dividing 15.0 g by 164.1 g/mol, which gives approximately 0.0914 moles. Since each formula unit of Ca(NO3)2 produces 2 moles of NO3- ions, the moles of NO3- ions is 0.0914 * 2 = 0.1828 moles. Finally, divide the moles of NO3- ions by the volume of the solution in liters (0.300 L) to find the concentration: 0.1828 moles / 0.300 L = 0.609 M.

What Is the Concentration of NO3- Ions in a Solution

What Is the Concentration of NO₃^- Ions in a Solution