What is the concentration of HCl in the final solution when 65 mL of a 9.0 M HCl solution is diluted with pure water to a total volume of 0.15 L? A) 2.1 × 10^-² M B) 3.9 M C) 21 M D) 3.9 × 10³ M

Question

Quizplus · Accepted Answer

The moles of HCl in the original solution can be calculated as:
moles HCl = Molarity × Volume
moles HCl = 9.0 M × 0.065 L
moles HCl = 0.585 mol
To calculate the final concentration, we need to use the fact that moles of solute remains constant after dilution:
moles HCl = Molarity × Volume
0.585 mol = Molarity × 0.15 L
Molarity = 3.9 M

What Is the Concentration of HCl in the Final Solution