How many milliliters of a 0.266 M CsNO₃ solution are required to make 150.0 mL of 0.075 M CsNO₃ solution? A) 53.2 mL B) 42.3 mL C) 18.8 mL D) 23.6 mL E) 35.1 mL

Question

Quizplus · Accepted Answer

The equation we use here is M1V1 = M2V2, where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.
We are given:
- M1 = 0.266 M
- M2 = 0.075 M
- V2 = 150.0 mL
We need to find V1, the initial volume.
Using the equation, we can rearrange to solve for V1:
V1 = (M2V2)/M1
V1 = (0.075 M)(150.0 mL)/(0.266 M)
V1 = 42.3 mL
Therefore, the best choice is B: 42.3 mL.

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