How many moles of CH₃CH₂Cl are contained in 548 mL of 0.0788 M CH₃CH₂Cl solution? A) 4.32 × 10^-2 mol B) 2.32 × 10^-2 mol C) 6.95 × 10^-2 mol D) 1.44 × 10^-2 mol E) 5.26 × 10^-2 mol

Question

Quizplus · Accepted Answer

To find the moles, use the formula: moles = molarity × volume (in liters). Convert 548 mL to liters (0.548 L) and multiply by 0.0788 M: 0.0788 × 0.548 = 4.32 × 10^-2 mol.

How Many Moles of CH3CH2Cl Are Contained in 548 ML

How Many Moles of CH₃CH₂Cl Are Contained in 548 ML